Construct an angle of $75^{\circ}$ and write the steps of construction.

(N/A) Steps of construction for $75^{\circ}$:
$1$. Draw a ray $OA$ with initial point $O$.
$2$. With $O$ as the center and any radius,draw an arc that intersects $OA$ at a point $P$.
$3$. With $P$ as the center and the same radius,draw an arc that intersects the previous arc at point $Q$. This represents $60^{\circ}$.
$4$. With $Q$ as the center and the same radius,draw another arc that intersects the first arc at point $R$. This represents $120^{\circ}$.
$5$. With $Q$ and $R$ as centers and radius more than half of $QR$,draw two arcs that intersect each other at point $S$. Join $OS$. The angle $\angle SOA = 90^{\circ}$.
$6$. Now,the angle between $60^{\circ}$ (point $Q$) and $90^{\circ}$ (point $S$) needs to be bisected.
$7$. With $Q$ and $S$ as centers and radius more than half of $QS$,draw two arcs that intersect at point $T$.
$8$. Join $OT$. The angle $\angle TOA = 75^{\circ}$.